2t^2+3t+20t=2t^2-6t

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Solution for 2t^2+3t+20t=2t^2-6t equation: 



2t^2+3t+20t=2t^2-6t

We move all terms to the left:

2t^2+3t+20t-(2t^2-6t)=0

We add all the numbers together, and all the variables

2t^2+23t-(2t^2-6t)=0

We get rid of parentheses

2t^2-2t^2+23t+6t=0

We add all the numbers together, and all the variables

29t=0

t=0/29

t=0

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